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Add Two Numbers.cpp
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Add Two Numbers.cpp
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/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode* addTwoNumbers(ListNode* l1, ListNode* l2) {
ListNode* head=NULL;
if(l1==NULL&&l2==NULL)//如果是空的直接返回NULL
{
return head;
}
if(l1==NULL)//如果l1空,l2不空,返回l2
{
return l2;
}
if(l2==NULL)//如果l2空。l1不空,返回l1
{
return l1;
}
ListNode* newNode=new ListNode(l1->val+l2->val);//都不空
head=newNode;
l1=l1->next;
l2=l2->next;
while(l1!=NULL&&l2!=NULL)
{
ListNode* CurrentNode=new ListNode(l1->val+l2->val);
newNode->next=CurrentNode;
newNode=newNode->next;
CurrentNode->next=NULL;
l1=l1->next;
l2=l2->next;
}
while(l1!=NULL&&l2==NULL)
{
ListNode* CurrentNode=new ListNode(l1->val);
newNode->next=CurrentNode;
newNode=newNode->next;
CurrentNode->next=NULL;
l1=l1->next;
}
while(l1==NULL&&l2!=NULL)
{
ListNode* CurrentNode=new ListNode(l2->val);
newNode->next=CurrentNode;
newNode=newNode->next;
CurrentNode->next=NULL;
l2=l2->next;
}
ListNode* p=head;
while(p!=NULL)
{
if(p->val>=10)
{
if(p->next!=NULL)
{
p->next->val=p->next->val+(p->val)/10;
p->val=(p->val)%10;
}
else//这边就是所如果你最后一位还有进位,那么你又要一个新的结点了。
{
ListNode* PP=new ListNode((p->val)/10);
p->next=PP;
PP->next=NULL;
p->val=(p->val)%10;
}
}
p=p->next;
}
return head;
}
};