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113.path-sum-ii.cpp
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113.path-sum-ii.cpp
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/*
* @lc app=leetcode id=113 lang=cpp
*
* [113] Path Sum II
*
* https://leetcode.com/problems/path-sum-ii/description/
*
* algorithms
* Medium (48.50%)
* Likes: 2654
* Dislikes: 85
* Total Accepted: 404.2K
* Total Submissions: 817.7K
* Testcase Example: '[5,4,8,11,null,13,4,7,2,null,null,5,1]\n22'
*
* Given the root of a binary tree and an integer targetSum, return all
* root-to-leaf paths where each path's sum equals targetSum.
*
* A leaf is a node with no children.
*
*
* Example 1:
*
*
* Input: root = [5,4,8,11,null,13,4,7,2,null,null,5,1], targetSum = 22
* Output: [[5,4,11,2],[5,8,4,5]]
*
*
* Example 2:
*
*
* Input: root = [1,2,3], targetSum = 5
* Output: []
*
*
* Example 3:
*
*
* Input: root = [1,2], targetSum = 0
* Output: []
*
*
*
* Constraints:
*
*
* The number of nodes in the tree is in the range [0, 5000].
* -1000 <= Node.val <= 1000
* -1000 <= targetSum <= 1000
*
*
*/
// @lc code=start
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
int pathSum(TreeNode* root, int sum) {
unordered_map<int, int> sumMap;
sumMap[0] = 1;
return DFS(root, 0, sum, 0, sumMap);
}
int DFS(TreeNode* root, int level, int sum, int curSum, unordered_map<int, int>& sumMap) {
if (root == nullptr)
return 0;
curSum += root->val;
int ans = 0;
if (sumMap.count(curSum - sum))
ans += sumMap[curSum - sum];
sumMap[curSum]++;
ans += DFS(root->left, level + 1, sum, curSum, sumMap);
ans += DFS(root->right, level + 1, sum, curSum, sumMap);
sumMap[curSum]--;
return ans;
}
};
// @lc code=end