12.integer-to-roman.cpp

/*
 * @lc app=leetcode id=12 lang=cpp
 *
 * [12] Integer to Roman
 *
 * https://leetcode.com/problems/integer-to-roman/description/
 *
 * algorithms
 * Medium (55.83%)
 * Likes:    1572
 * Dislikes: 3033
 * Total Accepted:    450.2K
 * Total Submissions: 796.5K
 * Testcase Example:  '3'
 *
 * Roman numerals are represented by seven different symbols: I, V, X, L, C, D
 * and M.
 * 
 * 
 * Symbol       Value
 * I             1
 * V             5
 * X             10
 * L             50
 * C             100
 * D             500
 * M             1000
 * 
 * For example, 2 is written as II in Roman numeral, just two one's added
 * together. 12 is written as XII, which is simply X + II. The number 27 is
 * written as XXVII, which is XX + V + II.
 * 
 * Roman numerals are usually written largest to smallest from left to right.
 * However, the numeral for four is not IIII. Instead, the number four is
 * written as IV. Because the one is before the five we subtract it making
 * four. The same principle applies to the number nine, which is written as IX.
 * There are six instances where subtraction is used:
 * 
 * 
 * I can be placed before V (5) and X (10) to make 4 and 9. 
 * X can be placed before L (50) and C (100) to make 40 and 90. 
 * C can be placed before D (500) and M (1000) to make 400 and 900.
 * 
 * 
 * Given an integer, convert it to a roman numeral.
 * 
 * 
 * Example 1:
 * 
 * 
 * Input: num = 3
 * Output: "III"
 * 
 * 
 * Example 2:
 * 
 * 
 * Input: num = 4
 * Output: "IV"
 * 
 * 
 * Example 3:
 * 
 * 
 * Input: num = 9
 * Output: "IX"
 * 
 * 
 * Example 4:
 * 
 * 
 * Input: num = 58
 * Output: "LVIII"
 * Explanation: L = 50, V = 5, III = 3.
 * 
 * 
 * Example 5:
 * 
 * 
 * Input: num = 1994
 * Output: "MCMXCIV"
 * Explanation: M = 1000, CM = 900, XC = 90 and IV = 4.
 * 
 * 
 * 
 * Constraints:
 * 
 * 
 * 1 <= num <= 3999
 * 
 * 
 */

// @lc code=start
class Solution {
public:
    string intToRoman(int num) {
        vector<int> values = {1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1};
        vector<string> pages = {"M", "CM", "D", "CD", "C", "XC", "L", "XL", "X", "IX", "V", "IV", "I"};
        string res;
        int i = 0;
        while (num > 0) {
            while (num >= values[i]) {
                num -= values[i];
                res += pages[i];
            }
            ++i;
        }
        return res;
    }
};
// @lc code=end