Find the Parity Outlier.ipynb

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  {
   "cell_type": "code",
   "execution_count": 1,
   "metadata": {
    "collapsed": true
   },
   "outputs": [],
   "source": [
    "from IPython.core.interactiveshell import InteractiveShell\n",
    "InteractiveShell.ast_node_interactivity = \"all\""
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "# Most Clever Answers on Codewars"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 33,
   "metadata": {
    "collapsed": true
   },
   "outputs": [],
   "source": [
    "#The first one\n",
    "def find_outlier(int):\n",
    "    odds = [x for x in int if x%2!=0]\n",
    "    evens= [x for x in int if x%2==0]\n",
    "    return odds[0] if len(odds)<len(evens) else evens[0]"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 35,
   "metadata": {
    "collapsed": true
   },
   "outputs": [],
   "source": [
    "#Trying to dissect why his function works.\n",
    "# So basically it gets two list, one for odd numbers, the other even. Get the number from the shorter one."
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 34,
   "metadata": {
    "collapsed": false,
    "scrolled": true
   },
   "outputs": [
    {
     "data": {
      "text/plain": [
       "11"
      ]
     },
     "execution_count": 34,
     "metadata": {},
     "output_type": "execute_result"
    }
   ],
   "source": [
    "find_outlier([2, 4, 0, 100, 4, 11, 2602, 36])"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 36,
   "metadata": {
    "collapsed": true
   },
   "outputs": [],
   "source": [
    "#This one is even better.\n",
    "def find_outlier(integers):\n",
    "    parity = [n % 2 for n in integers]\n",
    "    return integers[parity.index(sum(parity) == 1)]"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 37,
   "metadata": {
    "collapsed": false
   },
   "outputs": [
    {
     "data": {
      "text/plain": [
       "5"
      ]
     },
     "execution_count": 37,
     "metadata": {},
     "output_type": "execute_result"
    }
   ],
   "source": [
    "#Index is an amazing function\n",
    "T2.index(1)"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "# My Working Progress and Solution"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 2,
   "metadata": {
    "collapsed": true
   },
   "outputs": [],
   "source": [
    "T1 = [2, 4, 0, 100, 4, 11, 2602, 36]\n",
    "from functools import reduce"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 17,
   "metadata": {
    "collapsed": false,
    "scrolled": false
   },
   "outputs": [
    {
     "data": {
      "text/plain": [
       "[0, 0, 0, 0, 0, 1, 0, 0]"
      ]
     },
     "execution_count": 17,
     "metadata": {},
     "output_type": "execute_result"
    }
   ],
   "source": [
    "T2 = list(map(lambda x: x%2, T1))\n",
    "T2 "
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 30,
   "metadata": {
    "collapsed": false
   },
   "outputs": [
    {
     "data": {
      "text/plain": [
       "1"
      ]
     },
     "execution_count": 30,
     "metadata": {},
     "output_type": "execute_result"
    }
   ],
   "source": [
    "#Use list comprehension to get out the 1\n",
    "[result] = [e for e in T2 if e ==1 ]\n",
    "result"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 14,
   "metadata": {
    "collapsed": false
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   "outputs": [
    {
     "data": {
      "text/plain": [
       "2"
      ]
     },
     "execution_count": 14,
     "metadata": {},
     "output_type": "execute_result"
    }
   ],
   "source": [
    "#Learn Count Function\n",
    "string = \"Python is awesome, isn't it?\"\n",
    "substring = \"is\"\n",
    "\n",
    "count = string.count(substring)\n",
    "count"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 21,
   "metadata": {
    "collapsed": false
   },
   "outputs": [
    {
     "data": {
      "text/plain": [
       "7"
      ]
     },
     "execution_count": 21,
     "metadata": {},
     "output_type": "execute_result"
    },
    {
     "data": {
      "text/plain": [
       "7"
      ]
     },
     "execution_count": 21,
     "metadata": {},
     "output_type": "execute_result"
    }
   ],
   "source": [
    "#How about counting the elements in a list.\n",
    "T2.count(0)\n",
    "max(T2.count(0), T2.count(1))"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 28,
   "metadata": {
    "collapsed": false
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   "outputs": [
    {
     "data": {
      "text/plain": [
       "1"
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     "execution_count": 28,
     "metadata": {},
     "output_type": "execute_result"
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    {
     "data": {
      "text/plain": [
       "7"
      ]
     },
     "execution_count": 28,
     "metadata": {},
     "output_type": "execute_result"
    }
   ],
   "source": [
    "T2.count(max(T2))\n",
    "T2.count(min(T2))"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 24,
   "metadata": {
    "collapsed": false
   },
   "outputs": [],
   "source": [
    "set(T2)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 31,
   "metadata": {
    "collapsed": true
   },
   "outputs": [],
   "source": [
    "def find_outlier(integers):\n",
    "    MList = list(map(lambda x: x%2, integers))\n",
    "    maxC, minC = MList.count(max(MList)), MList.count(min(MList))\n",
    "    if maxC > minC:\n",
    "        #More 1 than 0, outlier is an even number\n",
    "        [result] = [e for e in integers if e%2 == 0]\n",
    "    else:\n",
    "        [result] = [e for e in integers if e%2 == 1]\n",
    "    return result"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "metadata": {
    "collapsed": true
   },
   "outputs": [],
   "source": [
    "#My final answer\n",
    "def find_outlier(integers):\n",
    "    MList = list(map(lambda x: x%2, integers))\n",
    "    maxC, minC = MList.count(max(MList)), MList.count(min(MList))\n",
    "    if maxC > minC:\n",
    "        [result] = [e for e in integers if e%2 == 0]\n",
    "    else:\n",
    "        [result] = [e for e in integers if e%2 == 1]\n",
    "    return result"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 32,
   "metadata": {
    "collapsed": false
   },
   "outputs": [
    {
     "data": {
      "text/plain": [
       "11"
      ]
     },
     "execution_count": 32,
     "metadata": {},
     "output_type": "execute_result"
    }
   ],
   "source": [
    "find_outlier([2, 4, 0, 100, 4, 11, 2602, 36])"
   ]
  }
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