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 # [Problem 725: Split Linked List in Parts](https://leetcode.com/problems/split-linked-list-in-parts/description/?envType=daily-question)
 
 ## Initial thoughts (stream-of-consciousness)
+- There are two parts to this problem: figuring out the sizes of each list segment and actually doing the splitting
+- Let's consider how to solve each in turn
 
 ## Refining the problem, round 2 thoughts
+- To figure out the sizes of the segments, I think we can:
+    - First, figure out how long the list is with an initial pass through the list.  Let's say the length is `n`.
+    - We can then compute a "base" size of each segment as `n // k`.  This is the "default" segment length, and it's also the minimum segment lenght.
+    - But some of the segments might need to be augmented by 1 additional element.  The number of segments that need augmenting is `n % k`.  We can create an `extra = n % k` variable, and then while `extra > 0` we augment the given segment with an additional element and then decrement `extra`.
+- Splitting the segments requires setting the `next` property of the last element of the previous segment to `None` and then appending the first element of the next segment to the to-be-outputted list of segments.
+- Note: I'm assuming that the output should be a list of heads of each segment's linked list, as opposed to "regular" (`list`) lists of the values of each segment's nodes
+- Assuming that this is the desired output format, I think I'm ready to implement the solution
 
 ## Attempted solution(s)
 ```python
-class Solution:  # paste your code here!
-    ...
+# Definition for singly-linked list.
+# class ListNode:
+#     def __init__(self, val=0, next=None):
+#         self.val = val
+#         self.next = next
+class Solution:
+    def splitListToParts(self, head: Optional[ListNode], k: int) -> List[Optional[ListNode]]:
+        # first compute the length of the list
+        n = 0
+        node = head
+        while node is not None:
+            node = node.next
+            n += 1
+
+        # now compile the actual segments
+        base_length = n // k
+        extras = n % k
+
+        segments = []
+        node = head
+        
+        for i in range(k):
+            part_head = node
+            part_length = base_length + (1 if extras > 0 else 0)
+            extras -= 1 if extras > 0 else 0
+
+            # finish off this segment
+            for j in range(part_length - 1):
+                if node:
+                    node = node.next
+            
+            # tie off the current segment and get ready for the next one
+            if node:
+                next_part = node.next
+                node.next = None
+                node = next_part
+
+            segments.append(part_head)
+
+        return segments
 ```
+- Given examples pass
+- Submitting...
+
+![Screenshot 2024-09-07 at 10 10 14 PM](https://github.com/user-attachments/assets/1c36ab06-c7e2-4b34-88f0-278f96c97e2d)
+
+Solved!
+