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15 | 15 |
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16 | 16 | # Complexity
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17 | 17 | - Time complexity : O(N)
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18 |
| -- Space complexity : O(N) |
| 18 | +- Space complexity : O(N) / O(1) |
19 | 19 | """
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20 | 20 |
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21 | 21 | from typing import List
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22 | 22 |
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23 | 23 |
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| 24 | +class Solution: |
| 25 | + def productExceptSelf(self, nums: List[int]) -> List[int]: |
| 26 | + |
| 27 | + n = len(nums) |
| 28 | + res = [1] * n |
| 29 | + |
| 30 | + prefix_product = 1 |
| 31 | + for i in range(n): |
| 32 | + res[i] = prefix_product |
| 33 | + prefix_product *= nums[i] |
| 34 | + |
| 35 | + suffix_product = 1 |
| 36 | + for i in range(n - 1, -1, -1): |
| 37 | + res[i] *= suffix_product |
| 38 | + suffix_product *= nums[i] |
| 39 | + |
| 40 | + |
| 41 | +""" |
24 | 42 | class Solution:
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25 | 43 | def productExceptSelf(self, nums: List[int]) -> List[int]:
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26 | 44 |
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27 | 45 | # 중복 계산을 피하는 방법?
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28 |
| - res_1 = [1] * len(nums) # [1, 1, 1, 1] |
29 |
| - res_2 = [1] * len(nums) # [1, 1, 1, 1] |
| 46 | + res_1 = [1] * len(nums) |
| 47 | + res_2 = [1] * len(nums) |
30 | 48 |
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31 | 49 | for n in range(1, len(nums)): # [1, 1(a), 2(ab), 6(abc)]
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32 | 50 | res_1[n] = res_1[n - 1] * nums[n - 1]
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33 | 51 |
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34 |
| - nums.reverse() # [4, 3, 2, 1] |
35 |
| - for n in range(1, len(nums)): # [1, 4(d), 12(cd), 24(bcd)] |
36 |
| - res_2[n] = res_2[n - 1] * nums[n - 1] |
| 52 | + # reverse X -> range를 반대로 |
| 53 | + for n in range(len(nums) - 1, -1, -1): # [1, 4(d), 12(cd), 24(bcd)] |
| 54 | + res_2[n] = res_2[n + 1] * nums[n + 1] |
37 | 55 |
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38 | 56 | res_2.reverse()
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39 | 57 | return [res_1[i] * res_2[i] for i in range(len(nums))]
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40 | 58 |
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41 | 59 |
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42 | 60 | sol = Solution()
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43 | 61 | print(sol.productExceptSelf([1, 2, 3, 4]))
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| 62 | +""" |
44 | 63 |
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45 | 64 |
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46 | 65 | """
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