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maximum-subarray solution
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maximum-subarray/ohgyulim.java

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class Solution {
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/* 시간 복잡도: O(N)
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* - for 루프: O(N)
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* 공간 복잡도: O(N), dp배열
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*/
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public int maxSubArray(int[] nums) {
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int[] dp = new int[nums.length];
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dp[0] = nums[0];
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int answer = nums[0];
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for (int i = 1; i < nums.length; i++) {
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dp[i] = Math.max(nums[i], dp[i - 1] + nums[i]);
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answer = Math.max(answer, dp[i]);
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}
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return answer;
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}
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}

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