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210+Course Schedule II.cpp
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210+Course Schedule II.cpp
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class Solution {
public:
vector<int> findOrder(int numCourses, vector<vector<int>>& prerequisites) {
// init
edges.resize(numCourses);
indeg.resize(numCourses);
for (auto info : prerequisites) {
edges[info[1]].push_back(info[0]); // 注意顺序 后边是需要先修的
++indeg[info[0]]; // 前者入度+1,因为有先修课
}
queue<int> q;
// 将所有入度为 0
for (int i = 0; i < numCourses; ++i) {
if (indeg[i] == 0) {
q.push(i);
}
}
while (!q.empty()) {
int u = q.front(); q.pop();
result.push_back(u);
for (int v : edges[u]) {
indeg[v]--;
// 如果有入度变为0的, 表示可以选了, 放入队列
if (indeg[v] == 0) {
q.push(v);
}
}
}
if (result.size() != numCourses) {
return {};
}
return result;
}
private:
// 存储有向图
vector<vector<int>> edges; // 把下标i修了才能修的其他课程 当下标i修了,这些课程入度都-1
// 存储每个节点的入度
vector<int> indeg;
// 存储答案
vector<int> result;
};
// dfs
class Solution {
private:
vector<vector<int>> edges;
vector<int> visited;
bool gValid = true;
public:
void dfs(int u) {
visited[u] = 1;
for (auto &v : edges[u]) {
if (visited[v] == 0) {
dfs(v);
if (!gValid) return;
} else if (visited[v] == 1) {
gValid = false;
return;
}
}
visited[u] = 2;
}
bool canFinish(int numCourses, vector<vector<int>>& prerequisites) {
edges.resize(numCourses);
visited.resize(numCourses);
for (auto &p : prerequisites) {
edges[p[1]].push_back(p[0]);
}
for (int i = 0; i < numCourses && gValid; ++i) {
if (!visited[i]) {
dfs(i);
}
}
return gValid;
}
};
// dfs2
class Solution {
private:
vector<vector<int>> edges;
vector<int> isVisit;
bool gValid = true;
public:
bool dfs(int u) {
if (isVisit[u] == 1) return false;
if (isVisit[u] == 2) return true;
isVisit[u] = 1;
for (auto v : edges[u]) {
if (!dfs(v)) return false;
}
isVisit[u] = 2;
return true;
}
bool canFinish(int numCourses, vector<vector<int>>& prerequisites) {
edges.resize(numCourses);
isVisit.resize(numCourses);
for (auto &p : prerequisites) {
edges[p[1]].push_back(p[0]);
}
for (int i = 0; i < numCourses; ++i) {
if (!dfs(i)) {
return false;
}
}
return true;
}
};