question: how to use long for custom scalar

[tenstad]

Custom scalar support - defaults to String but can be configured to deserialize to specific types

Is it possible to have the custom Long scalar be a Long instead of a String as the underlying type?
It is now quite strange to assert that the long values returned by the test-client is in fact strings.

Using this custom scalar:

    override fun willGenerateGraphQLType(type: KType): GraphQLType? = when (type.classifier) {
        Long::class -> ExtendedScalars.GraphQLLong

results in:

/**
 * Long type
 */
public typealias Long = String

[dariuszkuc]

Hello,

You need to configure your client with an appropriate converter -> docs.

Thanks,
Derek