From c283a0cae73618842ddd4059587d59366b93b1b1 Mon Sep 17 00:00:00 2001
From: Robotgiggle <88736742+Robotgiggle@users.noreply.github.com>
Date: Tue, 10 Sep 2024 11:12:22 -0400
Subject: [PATCH] Remove reference to nonexistent Combination Distillation

---
 .../main/resources/assets/hexcasting/lang/en_us.flatten.json5   | 2 +-
 1 file changed, 1 insertion(+), 1 deletion(-)

diff --git a/Common/src/main/resources/assets/hexcasting/lang/en_us.flatten.json5 b/Common/src/main/resources/assets/hexcasting/lang/en_us.flatten.json5
index 019b49ad4..5fa998401 100644
--- a/Common/src/main/resources/assets/hexcasting/lang/en_us.flatten.json5
+++ b/Common/src/main/resources/assets/hexcasting/lang/en_us.flatten.json5
@@ -1632,7 +1632,7 @@
         numlist: "Set operations are odd, in that some of them can accept two numbers or two lists, but not a combination thereof. Such arguments will be written as \"(num, num)|(list, list)\".$(br2)When numbers are used in those operations, they are being used as so-called binary \"bitsets\", lists of 1 and 0, true and false, \"on\" and \"off\".",
         
         "or.1": "Unifies two sets.",
-        "or.2": "As such:$(li)With two numbers at the top of the stack, combines them into a bitset containing every \"on\" bit in either bitset.$(li)With two lists, this creates a list of every element from the first list, plus every element from the second list that is not in the first list. This is similar to $(l:patterns/lists#hexcasting:add)$(action)Combination Distillation/$.",
+        "or.2": "As such:$(li)With two numbers at the top of the stack, combines them into a bitset containing every \"on\" bit in either bitset.$(li)With two lists, this creates a list of every element from the first list, plus every element from the second list that is not in the first list. This is somewhat similar to $(l:patterns/lists#hexcasting:add)$(action)Additive Distillation/$.",
         
         "and.1": "Takes the intersection of two sets.",
         "and.2": "As such:$(li)With two numbers at the top of the stack, combines them into a bitset containing every \"on\" bit present in $(italics)both/$ bitsets.$(li)With two lists, this creates a list of every element from the first list that is also in the second list.",