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Creating a new issue because this is, in my opinion, probably the most commonly encountered and annoying to work around issue caused by no-orphan rules:
Namely, the special case where A == B overlaps with the generic impl<T> From<T> for T.
It's also an instance where it's usually trivial to prove that the overlapping implementations are equivalent, though I realise this is probably not a productive path toward a solution.
The text was updated successfully, but these errors were encountered:
Creating a new issue because this is, in my opinion, probably the most commonly encountered and annoying to work around issue caused by no-orphan rules:
Namely, the special case where
A == B
overlaps with the genericimpl<T> From<T> for T
.It's also an instance where it's usually trivial to prove that the overlapping implementations are equivalent, though I realise this is probably not a productive path toward a solution.
The text was updated successfully, but these errors were encountered: