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<!DOCTYPE html>
<html lang="zh-CN" data-default-color-scheme="auto">
<head>
<meta charset="UTF-8">
<link rel="apple-touch-icon" sizes="76x76" href="/images/favicon.png">
<link rel="icon" href="/images/favicon.png">
<meta name="viewport"
content="width=device-width, initial-scale=1.0, maximum-scale=1.0, user-scalable=no, shrink-to-fit=no">
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<meta name="theme-color" content="#2f4154">
<meta name="description" content="小姜的博客">
<meta name="author" content="jerome">
<meta name="keywords" content="前端">
<title>小姜的博客</title>
<link rel="stylesheet" href="https://cdn.jsdelivr.net/npm/[email protected]/dist/css/bootstrap.min.css" />
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<script id="fluid-configs">
var Fluid = window.Fluid || {};
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</script>
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<meta name="generator" content="Hexo 5.4.0"></head>
<body>
<header style="height: 100vh;">
<nav id="navbar" class="navbar fixed-top navbar-expand-lg navbar-dark scrolling-navbar">
<div class="container">
<a class="navbar-brand"
href="/"> <strong>小姜的博客</strong> </a>
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data-target="#navbarSupportedContent"
aria-controls="navbarSupportedContent" aria-expanded="false" aria-label="Toggle navigation">
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</button>
<!-- Collapsible content -->
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</a>
</li>
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</li>
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</a>
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</a>
</li>
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<a class="nav-link" target="_self" data-toggle="modal" data-target="#modalSearch"> <i
class="iconfont icon-search"></i> </a>
</li>
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<a class="nav-link" target="_self"> <i
class="iconfont icon-dark" id="color-toggle-icon"></i> </a>
</li>
</ul>
</div>
</div>
</nav>
<div class="banner" id="banner" parallax=true
style="background: url('/images/bg-img.jpeg') no-repeat center center;
background-size: cover;">
<div class="full-bg-img">
<div class="mask flex-center" style="background-color: rgba(0, 0, 0, 0.5)">
<div class="page-header text-center fade-in-up">
<span class="h2" id="subtitle" title="Winter is coming">
</span>
</div>
<div class="scroll-down-bar">
<i class="iconfont icon-arrowdown"></i>
</div>
</div>
</div>
</div>
</header>
<main>
<div class="container nopadding-x-md">
<div class="py-5" id="board"
style=margin-top:0>
<div class="container">
<div class="row">
<div class="col-12 col-md-10 m-auto">
<div class="row mx-auto index-card">
<article class="col-12 col-md-12 mx-auto index-info">
<h1 class="index-header">
<a href="/2022/11/06/privacy-policy/" target="_self">
隐私政策
</a>
</h1>
<p class="index-excerpt">
<a href="/2022/11/06/privacy-policy/" target="_self">
本隐私政策（简称本政策）于 2022 年 11 月 7 日起发布并生效，本政策是龙岩创客科技有限公司快应用产品【典阅故事汇】（以下简称“本产品”）的隐私保护相关事项所订立的有效合约。您通过点击确认本协议或以其他方式选择接受本协议，即表示您与龙岩创客科技有限公司达成协议并同意接受本政策的全部以下约定内容。
【龙岩创客科技有限公司】系本产品的登记著作权人，依法享有本产品的著作权。
本产品由龙岩创客科技
</a>
</p>
<div class="index-btm post-metas">
<div class="post-meta mr-3">
<i class="iconfont icon-date"></i>
<time datetime="2022-11-06 14:49" pubdate>
2022-11-06
</time>
</div>
</div>
</article>
</div>
<div class="row mx-auto index-card">
<article class="col-12 col-md-12 mx-auto index-info">
<h1 class="index-header">
<a href="/2022/02/16/algorithm-face/" target="_self">
算法题汇总
</a>
</h1>
<p class="index-excerpt">
<a href="/2022/02/16/algorithm-face/" target="_self">
常规Promise12345678910111213141516171819202122232425262728293031323334353637383940414243444546474849505152535455const PENDING = 'PANDING'const FULFILLED = 'FULFILLED'const REJECTED =
</a>
</p>
<div class="index-btm post-metas">
<div class="post-meta mr-3">
<i class="iconfont icon-date"></i>
<time datetime="2022-02-16 23:25" pubdate>
2022-02-16
</time>
</div>
</div>
</article>
</div>
<div class="row mx-auto index-card">
<article class="col-12 col-md-12 mx-auto index-info">
<h1 class="index-header">
<a href="/2022/02/16/face-subjects/" target="_self">
面试题汇总
</a>
</h1>
<p class="index-excerpt">
<a href="/2022/02/16/face-subjects/" target="_self">
项目相关什么是快应用快应用是一种新的应用形态，快应用就是希望能够让用户无需下载安装，并且还能流畅的体验应用内容。
开发者主要利用前端知识与技能，以及对应的 IDE，手机设备就可以做原型的开发。快应用使用前端技术栈开发，原生渲染，同时具备 H5 与原生应用的双重优点。
网络知识https
客户端使用 https url 访问服务器，要求 web 服务器建立 ssl 链接
服务端接收到请求之后，将网络
</a>
</p>
<div class="index-btm post-metas">
<div class="post-meta mr-3">
<i class="iconfont icon-date"></i>
<time datetime="2022-02-16 23:25" pubdate>
2022-02-16
</time>
</div>
</div>
</article>
</div>
<div class="row mx-auto index-card">
<article class="col-12 col-md-12 mx-auto index-info">
<h1 class="index-header">
<a href="/2021/11/27/algorithm-test-11273/" target="_self">
最长回文子串
</a>
</h1>
<p class="index-excerpt">
<a href="/2021/11/27/algorithm-test-11273/" target="_self">
题目给你一个字符串 s，找到 s 中最长的回文子串。
示例 1123输入：s = "babad"输出："bab"解释："aba" 同样是符合题意的答案。
示例 212输入：s = "cbbd"输出："bb"
示例 312输入：s = "ac"输出："a"
</a>
</p>
<div class="index-btm post-metas">
<div class="post-meta mr-3">
<i class="iconfont icon-date"></i>
<time datetime="2021-11-27 14:43" pubdate>
2021-11-27
</time>
</div>
<div class="post-meta mr-3">
<i class="iconfont icon-category"></i>
<a href="/categories/%E7%AE%97%E6%B3%95%E9%A2%98/">算法题</a>
</div>
</div>
</article>
</div>
<div class="row mx-auto index-card">
<article class="col-12 col-md-12 mx-auto index-info">
<h1 class="index-header">
<a href="/2021/11/27/algorithm-test-11272/" target="_self">
字符串转换整数 (atoi)
</a>
</h1>
<p class="index-excerpt">
<a href="/2021/11/27/algorithm-test-11272/" target="_self">
题目请你来实现一个 myAtoi(string s) 函数，使其能将字符串转换成一个 32 位有符号整数（类似 C/C++ 中的 atoi 函数）。
函数 myAtoi(string s) 的算法如下：
读入字符串并丢弃无用的前导空格
检查下一个字符（假设还未到字符末尾）为正还是负号，读取该字符（如果有）。 确定最终结果是负数还是正数。 如果两者都不存在，则假定结果为正。
读入下一个字符，直到到
</a>
</p>
<div class="index-btm post-metas">
<div class="post-meta mr-3">
<i class="iconfont icon-date"></i>
<time datetime="2021-11-27 14:38" pubdate>
2021-11-27
</time>
</div>
<div class="post-meta mr-3">
<i class="iconfont icon-category"></i>
<a href="/categories/%E7%AE%97%E6%B3%95%E9%A2%98/">算法题</a>
</div>
</div>
</article>
</div>
<div class="row mx-auto index-card">
<article class="col-12 col-md-12 mx-auto index-info">
<h1 class="index-header">
<a href="/2021/11/27/algorithm-test-11271/" target="_self">
三数之和
</a>
</h1>
<p class="index-excerpt">
<a href="/2021/11/27/algorithm-test-11271/" target="_self">
题目给你一个包含 n 个整数的数组 nums，判断 nums 中是否存在三个元素 a，b，c ，使得 a + b + c = 0 ？请你找出所有和为 0 且不重复的三元组。
示例 112输入：nums = [-1,0,1,2,-1,-4]输出：[[-1,-1,2],[-1,0,1]]
示例 212输入：nums = []输出：[]
示例 312输入：nums = [0]输出：[]
答案123
</a>
</p>
<div class="index-btm post-metas">
<div class="post-meta mr-3">
<i class="iconfont icon-date"></i>
<time datetime="2021-11-27 14:36" pubdate>
2021-11-27
</time>
</div>
<div class="post-meta mr-3">
<i class="iconfont icon-category"></i>
<a href="/categories/%E7%AE%97%E6%B3%95%E9%A2%98/">算法题</a>
</div>
</div>
</article>
</div>
<div class="row mx-auto index-card">
<article class="col-12 col-md-12 mx-auto index-info">
<h1 class="index-header">
<a href="/2021/11/10/algorithm-test-11042/" target="_self">
删除链表的倒数第n个节点
</a>
</h1>
<p class="index-excerpt">
<a href="/2021/11/10/algorithm-test-11042/" target="_self">
题目给定一个链表，删除链表的倒数第 n 个节点并返回链表的头指针例如，给出的链表为: 1→2→3→4→5, n=2删除了链表的倒数第 n 个节点之后, 链表变为1→2→3→5.
示例 11234输入：{1,2},2 返回值：{2}
思路
运用快慢指针的思想
让 faster 先走 n 步，再让 faster 和 slower 一起走，这样在 fast
</a>
</p>
<div class="index-btm post-metas">
<div class="post-meta mr-3">
<i class="iconfont icon-date"></i>
<time datetime="2021-11-10 21:18" pubdate>
2021-11-10
</time>
</div>
</div>
</article>
</div>
<div class="row mx-auto index-card">
<article class="col-12 col-md-12 mx-auto index-info">
<h1 class="index-header">
<a href="/2021/11/08/algorithm-test-11041/" target="_self">
表达式求值
</a>
</h1>
<p class="index-excerpt">
<a href="/2021/11/08/algorithm-test-11041/" target="_self">
题目请写一个整数计算器，支持加减乘三种运算和括号。
示例 11234输入："1+2"返回值：3
示例 21234输入："(2*(3-4))*5"返回值：-10
示例 31234输入："3+2*3*4-1"返回值：26
思路对于「任何表达式」而言，我们都使用两个栈 nums 和 ops：
nums ： 存放所有的数字
ops ：存放
</a>
</p>
<div class="index-btm post-metas">
<div class="post-meta mr-3">
<i class="iconfont icon-date"></i>
<time datetime="2021-11-08 21:13" pubdate>
2021-11-08
</time>
</div>
<div class="post-meta mr-3">
<i class="iconfont icon-category"></i>
<a href="/categories/%E7%AE%97%E6%B3%95%E9%A2%98/">算法题</a>
</div>
</div>
</article>
</div>
<div class="row mx-auto index-card">
<article class="col-12 col-md-12 mx-auto index-info">
<h1 class="index-header">
<a href="/2021/11/04/algorithm-test-1104/" target="_self">
大数加法
</a>
</h1>
<p class="index-excerpt">
<a href="/2021/11/04/algorithm-test-1104/" target="_self">
题目以字符串的形式读入两个数字，编写一个函数计算它们的和，以字符串形式返回。
示例 1123456输入："1","99"返回值："100"说明：1+99=100
示例 21234输入："114514",""返回值："114514"
思路
先把两个数补全至相同长度，不够
</a>
</p>
<div class="index-btm post-metas">
<div class="post-meta mr-3">
<i class="iconfont icon-date"></i>
<time datetime="2021-11-04 20:32" pubdate>
2021-11-04
</time>
</div>
<div class="post-meta mr-3">
<i class="iconfont icon-category"></i>
<a href="/categories/%E7%AE%97%E6%B3%95%E9%A2%98/">算法题</a>
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<a href="/2021/11/03/algorithm-test-1103/" target="_self">
在二叉树中找到两个节点的最近公共祖先
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<a href="/2021/11/03/algorithm-test-1103/" target="_self">
题目给定一棵二叉树(保证非空)以及这棵树上的两个节点对应的val值 o1 和 o2，请找到 o1 和 o2 的最近公共祖先节点。
注：本题保证二叉树中每个节点的val值均不相同。
如当输入[3,5,1,6,2,0,8,#,#,7,4],5,1时，二叉树{3,5,1,6,2,0,8,#,#,7,4}如下图所示：
所以节点值为5和节点值为1的节点的最近公共祖先节点的节点值为3，所以对应的输出为3。
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