Table: Orders
+-----------------+----------+
| Column Name | Type |
+-----------------+----------+
| order_number | int |
| customer_number | int |
+-----------------+----------+
order_number is the primary key for this table.
This table contains information about the order ID and the customer ID.
Write an SQL query to find the customer_number
for the customer who has placed the largest number of orders.
The test cases are generated so that exactly one customer will have placed more orders than any other customer.
The query result format is in the following example.
Example 1:
Input:
Orders table:
+--------------+-----------------+
| order_number | customer_number |
+--------------+-----------------+
| 1 | 1 |
| 2 | 2 |
| 3 | 3 |
| 4 | 3 |
+--------------+-----------------+
Output:
+-----------------+
| customer_number |
+-----------------+
| 3 |
+-----------------+
Explanation:
The customer with number 3 has two orders, which is greater than either customer 1 or 2 because each of them only has one order.
So the result is customer_number 3.
Result
Runtime: 412 ms, faster than 86.66% of MySQL online submissions for Customer Placing the Largest Number of Orders.
Memory Usage: 0B, less than 100.00% of MySQL online submissions for Customer Placing the Largest Number of Orders.
Create table If Not Exists orders
(
order_number int,
customer_number int
);
Truncate table orders;
insert into orders (order_number, customer_number)
values ('1', '1');
insert into orders (order_number, customer_number)
values ('2', '2');
insert into orders (order_number, customer_number)
values ('3', '3');
insert into orders (order_number, customer_number)
values ('4', '3');
select customer_number
from Orders
group by customer_number
order by count(*) desc
limit 1;