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The original adversary oracle is equivalent to Inspector (k = 1)? #13

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nrryuya opened this issue Sep 12, 2019 · 0 comments
Open

The original adversary oracle is equivalent to Inspector (k = 1)? #13

nrryuya opened this issue Sep 12, 2019 · 0 comments
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nrryuya commented Sep 12, 2019

Related to #5

@nrryuya nrryuya added the question Further information is requested label Sep 12, 2019
This was referenced Sep 12, 2019
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