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IntegerReplacement.cpp
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IntegerReplacement.cpp
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// Source : https://leetcode.com/problems/integer-replacement/
// Author : Hao Chen
// Date : 2016-11-04
/***************************************************************************************
*
* Given a positive integer n and you can do operations as follow:
*
* If n is even, replace n with n/2.
* If n is odd, you can replace n with either n + 1 or n - 1.
*
* What is the minimum number of replacements needed for n to become 1?
*
* Example 1:
*
* Input:
* 8
*
* Output:
* 3
*
* Explanation:
* 8 -> 4 -> 2 -> 1
*
* Example 2:
*
* Input:
* 7
*
* Output:
* 4
*
* Explanation:
* 7 -> 8 -> 4 -> 2 -> 1
* or
* 7 -> 6 -> 3 -> 2 -> 1
***************************************************************************************/
class Solution {
public:
int integerReplacement_recursion(int n) {
if ( n <= 1) return 0; // recursive exited point
if ( n == INT_MAX ) return 32; // special case to avoid integer overflow.
if ( n % 2 == 0 ) return integerReplacement(n/2) + 1;
return min( integerReplacement(n+1), integerReplacement(n-1) ) + 1;
}
int integerReplacement_recursionWithCache(int n) {
static unordered_map<int, int> cache;
//if hitted the cache, just return the result
if (cache.find(n) != cache.end()) return cache[n];
int result;
if ( n <= 1) return 0; // recursive exited point
if ( n == INT_MAX ) return 32; // special case to avoid integer overflow.
if ( n % 2 == 0 ) result = integerReplacement(n/2) + 1;
else result = min( integerReplacement(n+1), integerReplacement(n-1) ) + 1;
//add into cache
cache[n] = result;
return result;
}
int integerReplacement_simple(int n){
int ans = 0;
size_t m = n;
while (1 != m) {
if (1 == (m & 1)) {
if (m==3) --m; //special case
else m = (m&0b11^0b01) ? m + 1 : m - 1;
}
else m >>= 1;
++ans;
}
return ans;
}
int integerReplacement(int n) {
return integerReplacement_recursionWithCache(n);
return integerReplacement_simple(n);
}
};