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Now dataset X={x1,x2,x3...,xn},shape=[n,m], x1,x2,...,xn are samples of X.
And label data y.shape=[n,k]
If I use a time window with length of 2,then after reshape: X= tf.reshape(X,[int(n/2), 2, m]) X.shape=[n/2,m]
But I have a problem in getting the cost by formula, cost_rnn = tf.reduce_mean(tf.nn.softmax_cross_entropy_with_logits(logits=y_ , labels=y))
because both X and y have different shape.
Now dataset X={x1,x2,x3...,xn},
shape=[n,m]
, x1,x2,...,xn are samples of X.And label data
y.shape=[n,k]
If I use a time window with length of 2,then after reshape:
X= tf.reshape(X,[int(n/2), 2, m])
X.shape=[n/2,m]
But I have a problem in getting the cost by formula,
cost_rnn = tf.reduce_mean(tf.nn.softmax_cross_entropy_with_logits(logits=y_ , labels=y))
because both X and y have different shape.
Anybody knows how to solve this problem?
现在,有数据集X={x1,x2,x3...,xn},
shape=[n,m]
其中,x1包含多个变量,
shape=[m]
.比如,X=[[1,10,100],[2,20,200],[3,30,300]],可以看做X由多个样本x1,x2,...组成的。
标签样本y={y1,y2,...yn},
shape=[n,k]
,比如,Y=[[1,0,0],[0,1,0],[0,0,1]]。
这个
LSTM
如果序列化数据的话,比如说,用时间窗time_step=2
,X= tf.reshape(X,[int(n/2), 2, m])
那么,序列化之后的样本,X就只有n-1 个了,
shape=[n/2,m]
这样,由于维度不一样,就无法求出
cost
了cost_rnn = tf.reduce_mean(tf.nn.softmax_cross_entropy_with_logits(logits=y_rnn, labels=y))
针对这种数据集应该怎样处理?
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