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"将其两边都乘上 x^n, 得到" 后面的式子中的 x 似乎都应该是 1 / x... |
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效果是一样的，$f(x)=g(x) \iff f(\frac{1}{x}) = g(\frac{1}{x})$ |
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https://oi-wiki.org/math/poly/div-mod/
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