ot.da.SinkhornTransport : does barycentric transform work for metric!='sqeuclidean'? #752
Unanswered
samarth4149
asked this question in
Q&A
Replies: 1 comment
-
This is a very good question! No it does not! While the euclidean barycentric mapping makes sens it is indeed not the proper barycentric mapping for any loss. We should definitely add this to the documentation and begin implementing for other losses (which is much more complex since it will require to solve optimization problems on several of them) |
Beta Was this translation helpful? Give feedback.
0 replies
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment
Uh oh!
There was an error while loading. Please reload this page.
-
Hi,
I'm unsure whether the transform the way it is currently computed using the coupling matrix would work for a metric which is not the l_2 norm going by equations 13 and 14 here. Would this for instance, work with cosine distance metric?
Cosine also seems to pose the following question : Would the final transformed source examples then be correct up to a multiplicative factor?
Much appreciated!
Beta Was this translation helpful? Give feedback.
All reactions