Error in App.open failed: C:/Program not found on Windows Machine

[AnandSingh314]

On Windows machine program/process will be in C:/Program Files (x86)/.... The absolute path could have space in between. The windows implementation of OSUtil class which is WinUtil class is causing issue since it is taking the full process same in a single string, & later separating the parameters with space separator logic.

I would suggest for taking the process/program name separately while creating the App object.

[debug] RunTimeAPI: loadLib: WinUtil.dll
[debug] WinUtil.getApp: C:/Program Files (x86)/Cisco/Cisco AnyConnect Secure Mobility Client/vpnui.exe
[debug] App.create: [-1:C:/Program]
true
[debug] WinUtil.getApp: C:/Program
false
[debug] WinUtil.getApp: C:/Program
[debug] WinUtil.getApp: 10504
[error] App.open failed: C:/Program not found
[debug] highlight R[139,395 433x394]@s(0)[0,0 1920x1080] E:Y, T:3.0 for 2.0 secs
app.isValid() => false
app.window() => null
app.isRunning() => false
app.getName() => C:/Program
[debug] RunTimeAPI: final cleanup
[debug] FileManager: deleteFileOrFolder:

[glitchassassin]

Does this work?

App('"C:/Program Files (x86)/Cisco/Cisco AnyConnect Secure Mobility Client/vpnui.exe"')

[HelioGuilherme66]

This is how I start my app:

import subprocess
subprocess.Popen(["C:\\Program Files\\Internet Explorer\\iexplore.exe", "http://my.URL.under.test/"])

[glitchassassin]

You should be able to use:

t = App.open('"C:\\Program Files\\Internet Explorer\\iexplore.exe" http://my.URL.under.test/')

I think the general rule is "if it works on the command line, it should work with App.open()". In this case, put double quotes around the path/executable name so it's recognized as a single token.

[RaiMan]

I have to check.
App should interpret the given string or even list/array of strings as Python's subprocess.Popen does it.