Summary

From Jun 5th,

badumbatish:

does parsing expression in parser.parse_expr() act the same as parsing outside? I called parse_expr (with no arguments) with current token of the first num1 and it kept on parsing until the right parenthesis of asm!

    unsafe {
        asm!(
            "add {0}, {0}",
            inout(reg) num1 => num1,
            in(reg) num2,
        );
    }

Reproducer

I tried this code:

    unsafe {
        asm!(
            "add {0}, {0}",
            inout(reg) num1 => num1,
            in(reg) num2,
        );
    }

Does the code make use of any (1.49) nightly feature ?

• Nightly

Godbolt link

No response

Actual behavior

Currently the inline assembly uses 2 identifier token checks, one for num1 before the =>, one for num1 after the =>

Expected behavior

I expected to be able to use parse_expr for both identifier, meaning I would want to call parse_expr(), then check for => , then call parse_expr() again without parse_expr eating up all token from the token stream

GCC Version

#3098