README_EN.md

1805. Number of Different Integers in a String

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Description

You are given a string word that consists of digits and lowercase English letters.

You will replace every non-digit character with a space. For example, "a123bc34d8ef34" will become " 123  34 8  34". Notice that you are left with some integers that are separated by at least one space: "123", "34", "8", and "34".

Return the number of different integers after performing the replacement operations on word.

Two integers are considered different if their decimal representations without any leading zeros are different.

 

Example 1:

Input: word = "a123bc34d8ef34"
Output: 3
Explanation: The three different integers are "123", "34", and "8". Notice that "34" is only counted once.

Example 2:

Input: word = "leet1234code234"
Output: 2

Example 3:

Input: word = "a1b01c001"
Output: 1
Explanation: The three integers "1", "01", and "001" all represent the same integer because
the leading zeros are ignored when comparing their decimal values.

 

Constraints:

• 1 <= word.length <= 1000
• word consists of digits and lowercase English letters.

Solutions

Python3

class Solution:
    def numDifferentIntegers(self, word: str) -> int:
        s = set()
        i, n = 0, len(word)
        while i < n:
            if word[i].isdigit():
                while i < n and word[i] == '0':
                    i += 1
                j = i
                while j < n and word[j].isdigit():
                    j += 1
                s.add(word[i: j])
                i = j
            i += 1
        return len(s)

Java

class Solution {
    public int numDifferentIntegers(String word) {
        Set<String> s = new HashSet<>();
        int n = word.length();
        for (int i = 0; i < n; ++i) {
            if (Character.isDigit(word.charAt(i))) {
                while (i < n && word.charAt(i) == '0') {
                    ++i;
                }
                int j = i;
                while (j < n && Character.isDigit(word.charAt(j))) {
                    ++j;
                }
                s.add(word.substring(i, j));
                i = j;
            }
        }
        return s.size();
    }
}

C++

class Solution {
public:
    int numDifferentIntegers(string word) {
        unordered_set<string> s;
        int n = word.size();
        for (int i = 0; i < n; ++i) {
            if (isdigit(word[i])) {
                while (i < n && word[i] == '0') ++i;
                int j = i;
                while (j < n && isdigit(word[j])) ++j;
                s.insert(word.substr(i, j - i));
                i = j;
            }
        }
        return s.size();
    }
};

Go

func numDifferentIntegers(word string) int {
	s := map[string]struct{}{}
	n := len(word)
	for i := 0; i < n; i++ {
		if word[i] >= '0' && word[i] <= '9' {
			for i < n && word[i] == '0' {
				i++
			}
			j := i
			for j < n && word[j] >= '0' && word[j] <= '9' {
				j++
			}
			s[word[i:j]] = struct{}{}
			i = j
		}
	}
	return len(s)
}

TypeScript

function numDifferentIntegers(word: string): number {
    return new Set(
        word
            .replace(/\D+/g, ' ')
            .trim()
            .split(' ')
            .filter(v => v !== '')
            .map(v => v.replace(/^0+/g, '')),
    ).size;
}

Rust

use std::collections::HashSet;
impl Solution {
    pub fn num_different_integers(word: String) -> i32 {
        let s = word.as_bytes();
        let n = s.len();
        let mut set = HashSet::new();
        let mut i = 0;
        while i < n {
            if s[i] >= b'0' && s[i] <= b'9' {
                let mut j = i;
                while j < n && s[j] >= b'0' && s[j] <= b'9' {
                    j += 1;
                }
                while i < j - 1 && s[i] == b'0' {
                    i += 1;
                }
                set.insert(String::from_utf8(s[i..j].to_vec()).unwrap());
                i = j;
            } else {
                i += 1;
            }
        }
        set.len() as i32
    }
}

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