You are given an array nums
that consists of non-negative integers. Let us define rev(x)
as the reverse of the non-negative integer x
. For example, rev(123) = 321
, and rev(120) = 21
. A pair of indices (i, j)
is nice if it satisfies all of the following conditions:
0 <= i < j < nums.length
nums[i] + rev(nums[j]) == nums[j] + rev(nums[i])
Return the number of nice pairs of indices. Since that number can be too large, return it modulo 109 + 7
.
Example 1:
Input: nums = [42,11,1,97] Output: 2 Explanation: The two pairs are: - (0,3) : 42 + rev(97) = 42 + 79 = 121, 97 + rev(42) = 97 + 24 = 121. - (1,2) : 11 + rev(1) = 11 + 1 = 12, 1 + rev(11) = 1 + 11 = 12.
Example 2:
Input: nums = [13,10,35,24,76] Output: 4
Constraints:
1 <= nums.length <= 105
0 <= nums[i] <= 109
class Solution:
def countNicePairs(self, nums: List[int]) -> int:
def rev(x):
y = 0
while x:
y = y * 10 + x % 10
x //= 10
return y
cnt = Counter(x - rev(x) for x in nums)
mod = 10**9 + 7
return sum(v * (v - 1) // 2 for v in cnt.values()) % mod
class Solution:
def countNicePairs(self, nums: List[int]) -> int:
def rev(x):
y = 0
while x:
y = y * 10 + x % 10
x //= 10
return y
ans = 0
mod = 10**9 + 7
cnt = Counter()
for x in nums:
y = x - rev(x)
ans += cnt[y]
cnt[y] += 1
return ans % mod
class Solution {
public int countNicePairs(int[] nums) {
Map<Integer, Integer> cnt = new HashMap<>();
for (int x : nums) {
int y = x - rev(x);
cnt.merge(y, 1, Integer::sum);
}
final int mod = (int) 1e9 + 7;
long ans = 0;
for (int v : cnt.values()) {
ans = (ans + (long) v * (v - 1) / 2) % mod;
}
return (int) ans;
}
private int rev(int x) {
int y = 0;
for (; x > 0; x /= 10) {
y = y * 10 + x % 10;
}
return y;
}
}
class Solution {
public int countNicePairs(int[] nums) {
Map<Integer, Integer> cnt = new HashMap<>();
final int mod = (int) 1e9 + 7;
int ans = 0;
for (int x : nums) {
int y = x - rev(x);
ans = (ans + cnt.getOrDefault(y, 0)) % mod;
cnt.merge(y, 1, Integer::sum);
}
return ans;
}
private int rev(int x) {
int y = 0;
for (; x > 0; x /= 10) {
y = y * 10 + x % 10;
}
return y;
}
}
class Solution {
public:
int countNicePairs(vector<int>& nums) {
auto rev = [](int x) {
int y = 0;
for (; x > 0; x /= 10) {
y = y * 10 + x % 10;
}
return y;
};
unordered_map<int, int> cnt;
for (int& x : nums) {
int y = x - rev(x);
cnt[y]++;
}
long long ans = 0;
const int mod = 1e9 + 7;
for (auto& [_, v] : cnt) {
ans = (ans + 1ll * v * (v - 1) / 2) % mod;
}
return ans;
}
};
class Solution {
public:
int countNicePairs(vector<int>& nums) {
auto rev = [](int x) {
int y = 0;
for (; x > 0; x /= 10) {
y = y * 10 + x % 10;
}
return y;
};
unordered_map<int, int> cnt;
int ans = 0;
const int mod = 1e9 + 7;
for (int& x : nums) {
int y = x - rev(x);
ans = (ans + cnt[y]++) % mod;
}
return ans;
}
};
func countNicePairs(nums []int) (ans int) {
rev := func(x int) (y int) {
for ; x > 0; x /= 10 {
y = y*10 + x%10
}
return
}
cnt := map[int]int{}
for _, x := range nums {
y := x - rev(x)
cnt[y]++
}
const mod int = 1e9 + 7
for _, v := range cnt {
ans = (ans + v*(v-1)/2) % mod
}
return
}
func countNicePairs(nums []int) (ans int) {
rev := func(x int) (y int) {
for ; x > 0; x /= 10 {
y = y*10 + x%10
}
return
}
cnt := map[int]int{}
const mod int = 1e9 + 7
for _, x := range nums {
y := x - rev(x)
ans = (ans + cnt[y]) % mod
cnt[y]++
}
return
}
/**
* @param {number[]} nums
* @return {number}
*/
var countNicePairs = function (nums) {
const rev = x => {
let y = 0;
for (; x > 0; x = Math.floor(x / 10)) {
y = y * 10 + (x % 10);
}
return y;
};
const cnt = new Map();
for (const x of nums) {
const y = x - rev(x);
cnt.set(y, (cnt.get(y) | 0) + 1);
}
let ans = 0;
const mod = 1e9 + 7;
for (const [_, v] of cnt) {
ans = (ans + Math.floor((v * (v - 1)) / 2)) % mod;
}
return ans;
};
/**
* @param {number[]} nums
* @return {number}
*/
var countNicePairs = function (nums) {
const rev = x => {
let y = 0;
for (; x > 0; x = Math.floor(x / 10)) {
y = y * 10 + (x % 10);
}
return y;
};
let ans = 0;
const mod = 1e9 + 7;
const cnt = new Map();
for (const x of nums) {
const y = x - rev(x);
const v = cnt.get(y) | 0;
ans = (ans + v) % mod;
cnt.set(y, v + 1);
}
return ans;
};