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Bug in a workflow with 2 path to the same app #40
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Hola, I think you're right! It should work like this. Right now, it works with AND rather than OR between them, meaning everything has to match going into the same node. The reason it hasn't been explored enough is probably because we've done what's seen below all along instead. The piece of code that handles this is also in the app itself, and can be seen here: https://github.com/frikky/Shuffle/blob/7a388f3c055baac37cc0a20ba583f4380f8f1561/backend/app_sdk/app_base.py#L1996 Do you think the best way to handle it may be to see if just one matches? It would just be a counter, checking if it's more than 0 at that point. It may also break someone elses workflow, but I totally do agree with this one. |
Hum ok the thinking is different than what I had in mind. But I think it translates to a branch should be an OR. So as soon as any branch goes to a node, the node executes. It would work in both examples we have in this thread. With your examples it works out of the box, and for my example I don't have to add an empty node between the router and the node B |
The way to handle "the node executes if all branches are true" would be through conditions in the output of the previous nodes. |
Btw, what I have in mind when I see this type of workflow is a "pipe and filter" architectural pattern (documentation bellow). https://www.dossier-andreas.net/software_architecture/pipe_and_filter.html |
Small clarification: it will ALWAYS wait for all previous nodes to have done something before executing, even when just one has to be correct. This is to ensure that we're taking all results into account, and it's not running the workflow in the wrong order This should be working when we update our apps to the latest SDK which has a proper fix for it :) |
I have the following workflow with 2 path possible to the same node:
Option 1: if $exec.fields contains computerName, do node A, then do node B
Option 2: if $exec.fields does not contains computerName, do node B.
However, when testing with a case where the Option 1 should be followed, the node B is never executed because the condition for the Option 2 is not fulfilled (that's the reason given when looking at the output of the skipped node B).
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