Word_counter.py

def word_counter(text):

    """
    This function first splits the 'text', if the two words contain space between them it creates a
    list consisting of the two words and a blanK value as a compensation to the space deleted and then 
    it it deletes the blanK string.
    Analysis of lines of code:-
    (1)Spliting the 'text' into words and blanK strings.
    (2)Creating a new variable which stores a list which is filtered version of the list generated by 
       spliting the 'text'.
    (3)Returns a message that tells how many words are in the text

    What is a blanK string?
    Suppose the text is 'Hello World'. When this is splited, the list so formed is ['Hello','','World']
    Now the second item in the list is a blanK string  
    """
    words = text.split(' ')
    pure_words = list(filter(lambda x: x != "", words))
    return f'''In the text file, there are {len(pure_words)} words'''

def list_of_words_from_text(text):

   """
   So, given a text, this function sorts out blanK spaces and returns a list of words without any blanK 
   spaces and null strings.
   for example:-
   text = "Hello World, this program is believed to give good lucK.
   When this function is used it will return the beow displayed list:-
   list_returned = ['Hello','World','this','program','is'.'believed','to','give','good','lucK.']
   """
   words = text.split(" ")
   valid_words = list(filter(lambda x: x != "", words))
   return valid_words