From 302b99f32ecbf546baad1c0e0ecea503c38ba895 Mon Sep 17 00:00:00 2001 From: mlamich1 <139090918+mlamich1@users.noreply.github.com> Date: Wed, 21 May 2025 18:16:58 +0000 Subject: [PATCH] Solution to Approximating Definite Integrals (IN2) --- source/calculus/source/04-IN/02.ptx | 140 +++++++++++++++++++++++++--- 1 file changed, 128 insertions(+), 12 deletions(-) diff --git a/source/calculus/source/04-IN/02.ptx b/source/calculus/source/04-IN/02.ptx index c2e8f7806..2a5fd4a9e 100644 --- a/source/calculus/source/04-IN/02.ptx +++ b/source/calculus/source/04-IN/02.ptx @@ -21,6 +21,9 @@ + + +

On the left-hand axes provided in Figure, sketch a labeled graph of the velocity function v(t) = 3. @@ -59,37 +62,78 @@ the units on the right-hand axes differ from those on the left. The right-hand axes will be used in question (d).

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+ +

+ The velocity function v(t)= 3 is a horizontal line at + y = 3 since the velocity is constant. +

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+ +

How far did the person travel during the two hours? How is this distance related to the area of a certain region under the graph of y = v(t)?

+
+ +

+ 6 +

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+ +

Find an algebraic formula, s(t), for the position of the person at time t, assuming that s(0) = 0. Explain your thinking.

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+ +

+ S(t) = 3t +

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+ +

On the right-hand axes provided in , sketch a labeled graph of the position function y = s(t).

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+ +

+ It is a line with constant slope of 3 +

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+ +

For what values of t is the position function s increasing? Explain why this is the case using relevant information about the velocity function v.

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+ +

+ S(t) is increasing for all t \geq 0 +

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+ + @@ -175,7 +219,8 @@ - + +

Using the grid, graph, and given data appropriately, @@ -183,30 +228,58 @@ You should use time intervals of width \Delta t = 0.5, choosing a way to use the function consistently to determine the height of each rectangle in order to approximate distance traveled.

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+ +

+ Distance \approx 3.7505 miles. +

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- + +

How could you get a better approximation of the distance traveled on [0,2]? Explain, and then find this new estimate.

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+ Use smaller intervals with \Delta t = 0.25 instead of 0.5 and new the estimate will be 3.87575. +

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- + +

Now suppose that you know that v is given by v(t) = 0.5t^3-1.5t^2+1.5t+1.5. Remember that v is the derivative of the walker's position function, s. Find a formula for s so that s' = v.

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+ +

+ S(t) = \frac{1}{8}t^4 -\frac{1}{2}t^3 + \frac{3}{4}t^2+ \frac{3}{2}t + C +

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Based on your work in (c), what is the value of s(2) - s(0)? What is the meaning of this quantity?

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+ s(2) - s(0) = 2 . It means The walker traveled exactly 2 miles between time t = 2 and t = 0 hrs. + +

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@@ -246,7 +319,7 @@

- Some of the values f(s_i) are negative. + C. Some of the values f(s_i) are negative.

@@ -330,7 +403,7 @@

- Some of the values f(s_i) are negative. + C. Some of the values f(s_i) are negative.

@@ -351,31 +424,74 @@ on the interval [2, 4] with 3 subintervals.

- + +

What are a and b in this case?

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+ a = 2 and b = 4 . +

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- + +

What is the value of n?

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+ n = 3 . +

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- + +

What are the values of the x_i?

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+ x_0 = 2 , x_1= \frac{8}{3} , x_2= \frac{10}{3} , and x_3= 4 +

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What are the values of the s_i?

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+ +

+ s_1= x_0 = 2 , s_2 = x_1= \frac{8}{3} , and s_3= x_2= \frac{10}{3} +

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What do you notice about the subinterval widths x_{i} - x_{i-1}?

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+ Each subinterval has same width of \frac{2}{3} +

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- + +

What is the value of the left Riemann sum?

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+ +

+ The left Riemann sum is approximately 3.995 +

+