test

[ainsleylaiuw]

test q

this is inline latex ? $ \dot{x} $ seems not

$$ \dot{x} $$

On its own line

[ainsleylaiuw]

answer 🎊

$$ \beta $$

[ainsleylaiuw]

$$ \dot{u} = -u + \frac{2}{1+v^2} \longrightarrow \dot{u} + v^{2}\dot{u} + u + uv^{2} = 2$$

$$ \dot{v} = -v + \frac{1}{1+u^2} \longrightarrow \dot{v} + u^{2}\dot{v} + v + vu^{2} = 1 $$