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p23.py
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p23.py
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# -*- coding: utf-8 -*-
"""
Created on Thu Mar 9 13:13:58 2017
@author: Refaia
"""
'''
import math
import time
def isAbundant(num) :
def sumDivisorsUnder(num) :
result = 1
for i in range(2, int(math.sqrt(num)) + 1) :
if num % i == 0 :
if i == num // i :
result += i
else :
result += i + (num // i)
return result
return sumDivisorsUnder(num) > num
def main() :
delta = time.time()
upperLimit = 28124
abundantNums = []
for i in range(12, upperLimit) :
if isAbundant(i) :
abundantNums.append(i)
sumOf2AbundantNums = [False for i in range(upperLimit)]
for i in range(0, len(abundantNums)) :
for j in range(0, len(abundantNums)) :
if abundantNums[i] + abundantNums[j] < upperLimit :
sumOf2AbundantNums[abundantNums[i] + abundantNums[j]] = True
sumNotAbundant = 12 * 23
delta1 = time.time()
for i in range(24, upperLimit) :
if sumOf2AbundantNums[i] == False :
sumNotAbundant += i
delta = time.time() - delta
delta1 = time.time() - delta1
print(sumNotAbundant, 'Total time:', delta,'// Sum time:', delta1)
if __name__ == '__main__' :
main()
'''
import math
import time
def isAbundant(num) :
def sumDivisorsUnder(num) :
result = 1
for i in range(2, int(math.sqrt(num)) + 1) :
if num % i == 0 :
if i == num // i :
result += i
else :
result += i + (num // i)
return result
return sumDivisorsUnder(num) > num
def sumOf2Abundant(abundantNums, num) :
if num % 2 == 0 :
if abundantNums[num // 2] :
return True
for i in range(1, (num // 2) + 1) :
if abundantNums[i] and abundantNums[num - i] :
return True
return False
def main() :
delta = time.time()
upperLimit = 28124
abundantNums = [False for i in range(upperLimit)]
for i in range(12, upperLimit) :
if isAbundant(i) :
abundantNums[i] = True
sumNotAbundant = 12 * 23 # 1 + ... + 23
delta1 = time.time()
for i in range(24, upperLimit) :
if not sumOf2Abundant(abundantNums, i) :
sumNotAbundant += i
delta1 = time.time() - delta1
delta = time.time() - delta
print(sumNotAbundant, 'Total time:', delta,'// Sum time:', delta1)
if __name__ == '__main__' :
main()