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Eclipse is showing me the following error: Could not get the value for parameter contextFolder for plugin execution default (ro.isdc.wro4j:wro4j-maven-plugin:1.7.6:run:default:generate-resources)
Solution-Add this in your properties. <properties> <project.build.sourceEncoding>UTF-8</project.build.sourceEncoding> <project.reporting.outputEncoding>UTF-8</project.reporting.outputEncoding> <java.version>1.8</java.version> <wro4j.version>1.8.0</wro4j.version> <angularjs.version>1.4.9</angularjs.version> <bootstrap.version>3.3.7-1</bootstrap.version> <jquery.version>2.2.4</jquery.version> <jasmine.version>2.0.0</jasmine.version> </properties>
Eclipse is showing me the following error: Could not get the value for parameter contextFolder for plugin execution default (ro.isdc.wro4j:wro4j-maven-plugin:1.7.6:run:default:generate-resources)
My pom.xml contains
Using version 1.7.8. This code was actually taken from an online tutorial by a Spring lead (Dave Syer) on making an app with Spring Security & Angular (https://spring.io/guides/tutorials/spring-security-and-angular-js/).
I should note that this error doesn't seem to be causing any ill effect either. Everything runs fine.
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