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main2.cpp
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main2.cpp
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/// Source : https://leetcode.com/problems/partition-to-k-equal-sum-subsets/description/
/// Author : liuyubobobo
/// Time : 2017-10-16
#include <iostream>
#include <vector>
#include <cassert>
#include <numeric>
#include <algorithm>
using namespace std;
/// Memory Search
/// We don't need to care about how many subset we didn't fill
///
/// Time Complexity: O((2^len(nums)) * len(nums))
/// Space Complexity: O((2^len(nums)))
class Solution {
private:
int subsum = 0;
bool dp[1<<16];
bool visited[1<<16];
public:
bool canPartitionKSubsets(vector<int>& nums, int k) {
int sum = accumulate(nums.begin(), nums.end(), 0);
// cout << "sum = " << sum << endl;
if(sum % k != 0)
return false;
subsum = sum / k;
// cout << subsum << endl;
sort(nums.begin(), nums.end());
if(nums[nums.size()-1] > subsum)
return false;
int len = (1<<nums.size());
// cout << len << endl;
for(int i = 0 ; i < len ; i ++){
dp[i] = false;
visited[i] = false;
}
return solve(nums, 0);
}
private:
bool solve(const vector<int>& nums, int state){
if(state == (1<<nums.size()) - 1)
return true;
if(visited[state])
return dp[state];
visited[state] = true;
return dp[state] = findSum(nums, state, 0, subsum);
}
bool findSum(const vector<int>& nums,
int state, int startIndex, int todo){
if(todo == 0)
return solve(nums, state);
for(int i = startIndex; i < nums.size() ; i ++)
if(todo >= nums[i]){
if((state & (1<<i)) == 0 && findSum(nums, state|(1<<i), i+1, todo-nums[i]))
return true;
}
else
break;
return false;
}
};
int main() {
int arr1[] = {4, 3, 2, 3, 5, 2, 1};
vector<int> vec1(arr1, arr1 + sizeof(arr1) / sizeof(int));
int k1 = 4;
if(Solution().canPartitionKSubsets(vec1, k1))
cout << "True" << endl;
else
cout << "False" << endl;
int arr2[] = {71,85,99,110,27,47,8,83,72,24,52,17,99};
vector<int> vec2(arr2, arr2 + sizeof(arr2) / sizeof(int));
int k2 = 13;
if(Solution().canPartitionKSubsets(vec2, k2))
cout << "True" << endl;
else
cout << "False" << endl;
int arr3[] = {39, 73, 52, 3, 9370};
vector<int> vec3(arr3, arr3 + sizeof(arr3) / sizeof(int));
int k3 = 3;
if(Solution().canPartitionKSubsets(vec3, k3))
cout << "True" << endl;
else
cout << "False" << endl;
return 0;
}