diff --git a/.vscode/settings.json b/.vscode/settings.json
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--- /dev/null
+++ b/.vscode/settings.json
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+{
+    "[python]": {
+        "editor.defaultFormatter": "ms-python.black-formatter"
+    },
+    "python.formatting.provider": "none"
+}
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diff --git a/kadone_algorithm/README.md b/kadone_algorithm/README.md
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+Given an array Arr[] of N integers. Find the contiguous sub-array(containing at least one number) which has the maximum sum and return its sum.
+
+
+Example 1:
+
+Input:
+N = 5
+Arr[] = {1,2,3,-2,5}
+Output:
+9
+Explanation:
+Max subarray sum is 9
+of elements (1, 2, 3, -2, 5) which 
+is a contiguous subarray.
+Example 2:
+
+Input:
+N = 4
+Arr[] = {-1,-2,-3,-4}
+Output:
+-1
+Explanation:
+Max subarray sum is -1 
+of element (-1)
+
+Your Task:
+You don't need to read input or print anything. The task is to complete the function maxSubarraySum() which takes Arr[] and N as input parameters and returns the sum of subarray with maximum sum.
+
+
+Expected Time Complexity: O(N)
+Expected Auxiliary Space: O(1)
+
+
+Constraints:
+1 ≤ N ≤ 106
+-107 ≤ A[i] ≤ 107
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diff --git a/kadone_algorithm/ka.py b/kadone_algorithm/ka.py
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+++ b/kadone_algorithm/ka.py
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+# User function Template for python3
+
+import math
+
+
+class Solution:
+    ##Complete this function
+    # Function to find the sum of contiguous subarray with maximum sum.
+    def maxSubArraySum(self, arr, N):
+        max = arr[0]
+        i = 0
+        while i < N:
+            print("i;", i)
+            j = i + 1
+            per = 1
+            while per + j-1 < N:
+                localMax = 0
+                marj = j
+                it = per
+                while it > 0 and marj < N:
+                    print("mars:", marj, arr[marj])
+                    localMax += arr[marj]
+                    marj += 1
+                    it -= 1
+                if localMax > max:
+                    max = localMax
+                    print("max", max)
+                per += 1
+            print("next:", per,i,j, max)
+            i += 1
+        return max
+
+
+def main():
+    N = 5
+    # N = 9
+    Arr = [1, 2, 3, -2, 5]
+    # Arr = [-2, 1, -3, 4, -1, 2, 1, -5, 4]
+    ob = Solution()
+    print(ob.maxSubArraySum(Arr, N))
+
+
+if __name__ == "__main__":
+    main()
diff --git a/missing_number_in_array/README.md b/missing_number_in_array/README.md
new file mode 100644
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+++ b/missing_number_in_array/README.md
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+Given an array of size N-1 such that it only contains distinct integers in the range of 1 to N. Find the missing element.
+
+Example 1:
+
+Input:
+N = 5
+A[] = {1,2,3,5}
+Output: 4
+Example 2:
+
+Input:
+N = 10
+A[] = {6,1,2,8,3,4,7,10,5}
+Output: 9
+
+Your Task :
+You don't need to read input or print anything. Complete the function MissingNumber() that takes array and N as input  parameters and returns the value of the missing number.
+
+
+Expected Time Complexity: O(N)
+Expected Auxiliary Space: O(1)
+
+
+Constraints:
+1 ≤ N ≤ 106
+1 ≤ A[i] ≤ 106
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diff --git a/missing_number_in_array/mnia.py b/missing_number_in_array/mnia.py
new file mode 100644
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--- /dev/null
+++ b/missing_number_in_array/mnia.py
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+#User function Template for python3
+
+
+class Solution:
+    def missingNumber(self,array,n): 
+        # code here
+        if n==2 and array[0]==1:
+            return 2
+        if n==2 and array[0]==2:
+            return 1
+        array.sort() 
+        i=0
+        while i<n-1:
+            if array[i]!=i+1:
+                return i+1
+            i+=1
+        return n
+
+
+#{ 
+ # Driver Code Starts
+#Initial Template for Python 3
+
+N = 10
+N = 5
+A = [6,1,2,8,3,4,7,10,5]
+A = [1,2,3,4]
+s=Solution().missingNumber(A,N)
+print(s)
+# } Driver Code Ends
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