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BinarySearchRotated.java
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BinarySearchRotated.java
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/* Java program to search an element in
sorted and rotated array using
single pass of Binary Search*/
//1) Find middle point mid = (l + h)/2
//2) If key is present at middle point, return mid.
//3) Else If arr[l..mid] is sorted
// a) If key to be searched lies in range from arr[l]
// to arr[mid], recur for arr[l..mid].
// b) Else recur for arr[mid+1..h]
//4) Else (arr[mid+1..h] must be sorted)
// a) If key to be searched lies in range from arr[mid+1]
// to arr[h], recur for arr[mid+1..h].
// b) Else recur for arr[l..mid]
class BinarySearchRotated {
// Returns index of key in arr[l..h]
// if key is present, otherwise returns -1
// arr, 0, n - 1, key
static int search(int arr[], int l, int h, int key)
{
if (l > h)
return -1;
int mid = (l + h) / 2;
if (arr[mid] == key)
return mid;
/* If arr[l...mid] first subarray is sorted */
if (arr[l] <= arr[mid]) {
/* As this subarray is sorted, we
can quickly check if key lies in
half or other half */
if (key >= arr[l] && key <= arr[mid])
return search(arr, l, mid - 1, key);
/*If key not lies in first half subarray,
Divide other half into two subarrays,
such that we can quickly check if key lies
in other half */
return search(arr, mid + 1, h, key);
}
/* If arr[l..mid] first subarray is not sorted,
then arr[mid... h] must be sorted subarray*/
if (key >= arr[mid] && key <= arr[h])
return search(arr, mid + 1, h, key);
return search(arr, l, mid - 1, key);
}
// main function
public static void main(String args[])
{
int arr[] = { 4, 7, 6, 5, 8, 9, 1, 2, 3 };
int n = arr.length;
int key = 7;
int i = search(arr, 0, n - 1, key);
if (i != -1)
System.out.println("Index: " + i);
else
System.out.println("Key not found");
}
}