How to host in Windows IIS 10.0?

[Raj9417]

I have manage simple flask app on windows IIS and it works. Sample web.config of normal flask app that work:

<?xml version="1.0" encoding="utf-8"?>
<configuration>
    <system.webServer>
        <modules>
            <remove name="WebDAVModule" />
        </modules>
        <handlers>
            <add name="Python FastCGI" path="*" verb="*" modules="FastCgiModule" 
            scriptProcessor="C:\Users\Vimalraj\AppData\Local\Programs\Python\Python36\python.exe|C:\Users\Vimalraj\AppData\Local\Programs\Python\Python36\Lib\site-packages\wfastcgi.py" resourceType="Unspecified" requireAccess="Script" />
        </handlers>
            <directoryBrowse enabled="true" />
    </system.webServer>
    <appSettings>
        <add key="WSGI_HANDLER" value="myapp2.manager" />
        <add key="PYTHONPATH" value="C:\API\facemaskapi\" />
    </appSettings>
</configuration>

But when I try with this flask-restplus-boilerplate it is not working. The web.config of the not working flask app:

<?xml version="1.0" encoding="utf-8"?>
<configuration>
    <system.webServer>
        <modules>
            <remove name="WebDAVModule" />
        </modules>
        <handlers>
            <add name="Python FastCGI" path="*" verb="*" modules="FastCgiModule" 
            scriptProcessor="C:\Users\Vimalraj\AppData\Local\Programs\Python\Python36\python.exe|C:\Users\Vimalraj\AppData\Local\Programs\Python\Python36\Lib\site-packages\wfastcgi.py" resourceType="Unspecified" requireAccess="Script" />
        </handlers>
            <directoryBrowse enabled="true" />
    </system.webServer>
    <appSettings>
        <add key="WSGI_HANDLER" value="manage.manager" />
        <add key="PYTHONPATH" value="C:\RESTFULAPI\API\" />
    </appSettings>
</configuration>

For the working version, the script name is "myapp2.py" and have "manager= Flask(name)" thus the WSGI_HANDLER value is "myapp2.manager".

I am not sure what should I put on the web.config of the not working version, currently the value is "manage.manager" where the script name is "manage.py" and I suspect "manager" is the startup line in the code.

My main line is as below:

if name == 'main':
manager.run(default_command="run")

run command as below:

@manager.command
def run():
app.run(host='127.0.0.1',port=7071)

Please help me in this Thank You.