You signed in with another tab or window. Reload to refresh your session.You signed out in another tab or window. Reload to refresh your session.You switched accounts on another tab or window. Reload to refresh your session.Dismiss alert
The Kuiper Exact Test is generalizable to r X c contingency tables. Just iterate over all tables with the same marginal totals, compute the probability of each, and add up all the probabilities less than or equal to the one observed.
The number of degrees of freedom is r * c - r - c + 1. For example:
2 X 2: 4 - 2 - 2 + 1 = 1
3 X 2: 6 - 3 - 2 + 1 = 2
3 X 3: 9 - 3 - 3 + 1 = 4
4 X 2: 8 - 4 - 2 + 1 = 3
4 X 3: 12 - 4 - 3 + 1 = 4
4 X 4: 16 - 4 - 4 + 1 = 9
Only 2 X 2 has only a single degree of freedom corresponding to a hyper-geometrically distributed variable, which is why it is the one most commonly supported.
Others can be supported via enumeration of multiple degrees of freedom, or via Monte Carlo simulation. Here is a recent article about the latter: https://arxiv.org/pdf/1507.00070.pdf
The text was updated successfully, but these errors were encountered:
dcwuser
changed the title
Kuiper Exact Test for arbitrary contingency tables
Fisher Exact Test for arbitrary contingency tables
Mar 16, 2018
The Kuiper Exact Test is generalizable to r X c contingency tables. Just iterate over all tables with the same marginal totals, compute the probability of each, and add up all the probabilities less than or equal to the one observed.
The number of degrees of freedom is r * c - r - c + 1. For example:
Only 2 X 2 has only a single degree of freedom corresponding to a hyper-geometrically distributed variable, which is why it is the one most commonly supported.
Others can be supported via enumeration of multiple degrees of freedom, or via Monte Carlo simulation. Here is a recent article about the latter: https://arxiv.org/pdf/1507.00070.pdf
The text was updated successfully, but these errors were encountered: