Batman and Tick-tack-toe

#include<stdio.h>
int main()
{
    int i,j,k=0,chance,n,t,x,dot,o,m;
    char arr[4][4];
    scanf("%d",&t);
    int arr2[t];
    for(m=0;m<t;m++)
        arr2[t]=0;
    for(m=0;m<t;m++)
    {
        x=0,dot=0,o=0;
        for(i=0;i<4;i++)
        {
            for(j=0;j<4;j++)
            {
                scanf("%c",&arr[i][j]);
                if(arr[i][j]=='x')
                    x++;
                else if(arr[i][j]=='.')
                    dot++;
                else
                    o++;
            }
        }
        if(x<=o)
            chance=1;//1 represents x's turn
        else
            chance=0;//0 reprsents o's turn
        if(chance==1)
        {
            i=0;
            //first we are gonna check columnwise
                k=0;//k is basically the parameter that decides whether or not the arrangement will be favourable
                for(j=0;j<4;j++)
                {
                    while(arr[i][j]!='o' && i<4)
                    {
                        if(arr[i][j]=='x')
                            k++;
                        k++;
                        i++;
                    }
                    if(k>=5)//i wrote 5 because there must be 3 spaces and 2 'x's to win
                    {
                        arr2[m]=1;//1 represents that we have YES
                        break;
                    }
                    else
                        k=0;
                }
            //now we'll check row wise
                if(k==0)
                {
                    j=0;
                    for(i=0;i<4;i++)
                    {
                        while(arr[i][j]!='o' && j<4)
                        {
                            if(arr[i][j]=='x')
                                k++;
                            k++;
                            j++;
                        }
                        if(k>=5)
                        {
                            arr2[m]=1;//1 represents that we have YES
                            break;
                        }
                        else
                            k=0;
                    }
                }
            //now we'll check diagonally
                if(k==0)
                {
                    i=0,j=0;
                    {
                        while(arr[i][j]!='o' && j<4 && i<4)
                        {
                            if(arr[i][j]=='x')
                                k++;
                            k++;
                            j++,i++;
                        }
                        if(k>=5)
                        {
                            arr2[m]=1;//1 represents that we have YES
                            break;
                        }
                        else
                            k=0;
                    }
                    if(k==0){
                    i=4,j=0;
                    while(arr[i][j]!='o' && j<4 && i<4)
                    {
                        if(arr[i][j]=='x')
                            k++;
                        k++;
                        j++,i--;
                    }
                    if(k>=5)
                    {
                        arr2[m]=1;//1 represents that we have YES
                        break;
                    }
                    else
                        k=0;
                    }
                }
        }
        else
        {
            i=0;
            //first we are gonna check columnwise
                k=0;
                int temp1=i,temp2=j;
                for(j=0;j<4;j++)
                {
                    while(arr[i][j]!='x' && i<4)
                    {
                        if(arr[i][j]=='o')
                            k++;
                        k++;
                        i++;
                    }
                    if(k>=5)
                    {
                        arr2[m]=1;//1 represents that we have YES
                        break;
                    }
                    else
                        k=0;
                }
            //now we'll check row wise
                if(k==0)
                {
                    j=0;
                    for(i=0;i<4;i++)
                    {
                        while(arr[i][j]!='x' && j<4)
                        {
                            if(arr[i][j]=='o')
                                k++;
                            k++;
                            j++;
                        }
                        if(k>=5)
                        {
                            arr2[m]=1;//1 represents that we have YES
                            break;
                        }
                        else
                            k=0;
                    }
                }
            //now we'll check diagonally
                if(k==0)
                {
                    i=0,j=0;
                    {
                        while(arr[i][j]!='x' && j<4 && i<4)
                        {
                            if(arr[i][j]=='o')
                                k++;
                            k++;
                            j++,i++;
                        }
                        if(k>=5)
                        {
                            arr2[m]=1;//1 represents that we have YES
                            break;
                        }
                        else
                            k=0;
                    }
                    if(k==0){
                    i=4,j=0;
                    while(arr[i][j]!='x' && j<4 && i<4)
                    {
                        if(arr[i][j]=='o')
                            k++;
                        k++;
                        j++,i--;
                    }
                    if(k>=5)
                    {
                        arr2[m]=1;//1 represents that we have YES
                        break;
                    }
                    else
                        k=0;
                    }
                }
        }
    }
    for(m=0;m<t;m++)
    {
        if(arr2[m]==1)
            printf("YES\n");
        else
            printf("NO\n");
    }
}