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Request capabilities #81
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Thanks for the suggestion! Can you explain a little more what you want? I'm not understanding how a single subdie coord could be two different die. "die1 X=3, Y=4; die2 X=3, Y=4;" Do you mean you have two different reticle shots like so?
This tool is not intended to be a gross-die-per-wafer calculator, so I don't think it makes sense to support reticles. Instead, this is supposed to be for viewing die data to see any wafer-location-dependent patterns that may show up. For example, when plotting oxide thickness, a hot spot in the oxidation chamber could cause thicker oxide in the lower-left part of the wafer. When I first wrote this, I did think about reticle support but I couldn't come up with a use case. Perhaps you can persuade me. Also, note that I have very little time these days so I may not get to adding the feature 😢. |
Hi Doug, Thank you for your reply and YES I'm mainly working on a RETICLE internal design. It is only a single reticle shot but with combination of up to 6 different die and different array and sub arrays. Reticle shot =1 (Reticle X, Reticle Y)Combination of 4 die with 4 x 4 arrayDie Sub Array - Note All die X dimension is equal, Die 1 & 2 Y is equal and Die 3 & 4 Y is equal#1 = 2 x 2 Please see attached sample reticle with an array of 4 x 4. |
Ah, I see what you mean. Sadly I didn't design the program to handle multiple die sizes 😞. If you don't care about the difference in Y sizes (maybe it's a difference of only a few percent and won't be noticeable?), you can still use this to plot data - it might just look a little funny. What you want to do is figure out function that tells you what the die type is. Based on your image, something like this might work: def die_type(x, y):
"""`x` and `y` are the integer die coordinates"""
# Top two rows
if y % 4 == 0 or y % 4 == 1:
if x % 4 == 0 or x % 4 == 1:
_type = 1
elif x % 4 == 2 or x % 4 == 3:
_type = 2
else:
raise ValueError("This shouldn't be possible.")
# Bottom two rows
elif y % 4 == 2:
_type = 3
elif y % 4 == 3:
_type = 4
else:
raise ValueError("How did you even get here???")
return _type You can then use that function to define the discrete bins. In wafer_map/wafer_map/example.py Line 142 in 5e2ea25
discrete_xyd = [(_x, _y, die_type(_x, _y))
for _x, _y, _
in xyd] You'll end up with something like this: That's about all you'll be able to do with the program in it's current state. You're welcome to try and make changes though! But I warn you - I think this code is pretty damn bad. My past self wasn't as good of programmer as I am today. |
Hi Doug, Thank you for help and reply. Will try your suggestion. Cheers, |
Hi Doug,
First of all thank you for writing this wafer_map app. It was great and nice to use.
Tool is working fine for me and this is not an issue but a nice to have capabilities request.
At the moment I'm working mainly in Chip RETICLE(Mask) preparation and planning.
Most of our designs has a multiple combination of die i.e. 4 die in 1 RETICLE shot(MASK) with different die arrays X=6, Y=6 and sub arrays of die i.e die1 X=3, Y=4; die2 X=3, Y=4; die3 X=6, Y=1 and die4 X=6, Y=1
I hope that my request is clear again thank you for making this wonderful wafer map app.
Thanks!
Fixrouter
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