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Confidence interval for eta^2 #612

Answered by bwiernik
kazz530 asked this question in Q&A
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There is no theoretical justification for N. The distribution of eta^2 follows the F distribution with the appropriate df.

Steiger used a maximum likelihood asymptotic approximation. Using the df is less biased and more accurate

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Answer selected by mattansb
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@kazz530
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Converted from issue

This discussion was converted from issue #611 on October 01, 2023 09:18.