Chapter 13 Exercise 3

[brainuser5705]

First off thanks for having this repo, it's definitely great to look at someone else's implementations of the exercises.

I believe for the last expression in Chapter 13 Exercise 3, the final type is a double, not a float.
I think the conversions take place in this order:

1. l is casted to a double since the cast operator takes precedence over the operations.
2. i/l results in i converting to an double and that makes the result '0.2' as a double.
3. l +0.2 results in l converting to a double and that makes the result '500.2' as a double.

I checked with the order Kochan listed, but I could be wrong?