sol.md

1. Initialize two pointers, slow and fast, to the head of the linked list.
2. Iterate over the linked list:
   • Move the slow pointer one node forward.
   • Move the fast pointer two nodes forward.
   • If the fast pointer and the slow pointer meet, then there is a cycle in the linked list.
3. If the fast pointer reaches the end of the linked list without meeting the slow pointer, then there is no cycle in the linked list.
4. If there is a cycle in the linked list, then the function returns the node where the slow pointer and the fast pointer meet.

Example:

Consider the following linked list: head -> 1 -> 2 -> 3 -> 4 -> 5 -> 3

The algorithm will work as follows:

Iteration	slow.val	fast.val
1	1	1
2	2	3
3	3	4
4	4	5
5	5	3

At the fifth iteration, the slow pointer and the fast pointer meet at the node 3. Therefore, the function returns the node 3.