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练习1.10 #39

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KushNee opened this issue May 26, 2015 · 0 comments

KushNee commented May 26, 2015

不知道什么原因，书中示例和维基百科上关于阿克曼函数的定义是不一致的。我修改了代码，但是不知道是否正确，希望能有人看一下。

(define (A x y)
    (cond ((= y 0) (A (- x 1) 1))
        ((= x 0) (+ y 1))
        (else (A (- x 1) (A x (- y 1)))))
)

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