find-the-parity-outlier.js

// You are given an array (which will have a length of at least 3, but could be very large) containing integers. The array is either entirely comprised of odd integers or entirely comprised of even integers except for a single integer N. Write a method that takes the array as an argument and returns this "outlier" N.

// Examples
// [2, 4, 0, 100, 4, 11, 2602, 36]
// Should return: 11 (the only odd number)

// [160, 3, 1719, 19, 11, 13, -21]
// Should return: 160 (the only even number)

// solution

function findOutlier(integers) {
  const evenInts = integers.filter((num) => num % 2 === 0 || num % 2 === -0);
  console.log(evenInts);
  const oddInts = integers.filter((num) => num % 2 !== 0 || num % 2 !== -0);
  console.log(oddInts);
  if (evenInts.length > oddInts.length) {
    return oddInts[0];
  } else {
    return evenInts[0];
  }
}