LeapYearCalculator.java

package com.TimBuchalka;
//Write a method isLeapYear with a parameter of type int named year. The parameter needs to be greater than or equal to 1 and less than or equal to 9999.
//If the parameter is not in that range return false. Otherwise, if it is in the valid range, calculate if the year is a leap year and return true.
//If it is a leap year, otherwise return false.
//
//To determine whether a year is a leap year, follow these steps:
//1. If the year is evenly divisible by 4, go to step 2. Otherwise, go to step 5.
//2. If the year is evenly divisible by 100, go to step 3. Otherwise, go to step 4.
//3. If the year is evenly divisible by 400, go to step 4. Otherwise, go to step 5.
//4. The year is a leap year (it has 366 days). The method isLeapYear needs to return true.
//5. The year is not a leap year (it has 365 days). The method isLeapYear needs to return false.
//
//Examples of input/output:
//* isLeapYear(-1600); → should return false since the parameter is not in range (1-9999)
//* isLeapYear(1600); → should return true since 1600 is a leap year
//* isLeapYear(2017); → should return false since 2017 is not a leap year
//* isLeapYear(2000);  → should return true because 2000 is a leap year

public class LeapYearCalculator {
    public static boolean isLeapYear(int year) {
        if ((year > 0) && (year < 9999)) {
            if (year % 4 != 0) {
                System.out.println(false);
                return false;
            } else if (year % 400 == 0) {
                System.out.println(true);
                return true;
            } else if (year % 100 == 0) {
                System.out.println(false);
                return false;
            } else
                System.out.println(true);
                return true;
        }
        System.out.println(false);
        return false;
    }
}