[ruby] Shadowing in lambda functions

[AndreiDreyer]

In the following code sample, the x in the do block shadows the x = 1 variable outside of the block, however the current implementation captures the x inside the do block as the x = 1 outside of the do block.

def foo(&block)
  block.call(2)
end

x = 1
foo do |x|
  puts x
end