From 97acefd283ad6b9d59876711c7e87bcc89a0dc2c Mon Sep 17 00:00:00 2001
From: HyprexDeva <96543076+hyprex-deva@users.noreply.github.com>
Date: Mon, 17 Oct 2022 19:13:08 +0530
Subject: [PATCH] Create calculator.py

---
 Python/calculator.py | 54 ++++++++++++++++++++++++++++++++++++++++++++
 1 file changed, 54 insertions(+)
 create mode 100644 Python/calculator.py

diff --git a/Python/calculator.py b/Python/calculator.py
new file mode 100644
index 0000000..901c5a0
--- /dev/null
+++ b/Python/calculator.py
@@ -0,0 +1,54 @@
+# Program make a simple calculator
+
+# This function adds two numbers
+def add(x, y):
+    return x + y
+
+# This function subtracts two numbers
+def subtract(x, y):
+    return x - y
+
+# This function multiplies two numbers
+def multiply(x, y):
+    return x * y
+
+# This function divides two numbers
+def divide(x, y):
+    return x / y
+
+
+print("Select operation.")
+print("1.Add")
+print("2.Subtract")
+print("3.Multiply")
+print("4.Divide")
+
+while True:
+    # take input from the user
+    choice = input("Enter choice(1/2/3/4): ")
+
+    # check if choice is one of the four options
+    if choice in ('1', '2', '3', '4'):
+        num1 = float(input("Enter first number: "))
+        num2 = float(input("Enter second number: "))
+
+        if choice == '1':
+            print(num1, "+", num2, "=", add(num1, num2))
+
+        elif choice == '2':
+            print(num1, "-", num2, "=", subtract(num1, num2))
+
+        elif choice == '3':
+            print(num1, "*", num2, "=", multiply(num1, num2))
+
+        elif choice == '4':
+            print(num1, "/", num2, "=", divide(num1, num2))
+        
+        # check if user wants another calculation
+        # break the while loop if answer is no
+        next_calculation = input("Let's do next calculation? (yes/no): ")
+        if next_calculation == "no":
+          break
+    
+    else:
+        print("Invalid Input")