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When std::function is put inside queued_task it is wrapped in callable resulting with two levels of type erasure which for a std::function<void()> is unnecessary.
The text was updated successfully, but these errors were encountered:
When
std::function
is put insidequeued_task
it is wrapped incallable
resulting with two levels of type erasure which for astd::function<void()>
is unnecessary.The text was updated successfully, but these errors were encountered: