Confusion on relational operators and generic types #944
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ProBaturay
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I was going to compare the numbers, I used the "<" operator, but it was not meant to create a generic type. Parentheses should solve the problem, but do I have to take the
b :: number
phrase into parentheses every time? Could it be achieved to make it without parentheses? Potentially a bug.Beta Was this translation helpful? Give feedback.
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