Given an array A
of integers, return the length of the longest arithmetic subsequence in A
.
Recall that a subsequence of A
is a list A[i_1], A[i_2], ..., A[i_k]
with 0 <= i_1 < i_2 < ... < i_k <= A.length - 1
, and that a sequence B
is arithmetic if B[i+1] - B[i]
are all the same value (for 0 <= i < B.length - 1
).
Example 1:
Input: [3,6,9,12] Output: 4 Explanation: The whole array is an arithmetic sequence with steps of length = 3.
Example 2:
Input: [9,4,7,2,10] Output: 3 Explanation: The longest arithmetic subsequence is [4,7,10].
Example 3:
Input: [20,1,15,3,10,5,8] Output: 4 Explanation: The longest arithmetic subsequence is [20,15,10,5].
Note:
2 <= A.length <= 2000
0 <= A[i] <= 10000
Related Topics:
Dynamic Programming
// OJ: https://leetcode.com/problems/longest-arithmetic-sequence/
// Author: github.com/lzl124631x
// Time: O(N^2)
// Space: O(N^2)
class Solution {
public:
int longestArithSeqLength(vector<int>& A) {
unordered_map<int, unordered_map<int, int>> m;
int ans = 0;
for (int n : A) {
m[n] = {};
for (auto &p : m) {
int d = n - p.first;
ans = max(ans, m[n][d] = p.second.count(d) ? p.second[d] + 1 : 2);
}
}
return ans;
}
};