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Assume you are an awesome parent and want to give your children some cookies. But, you should give each child at most one cookie.

Each child i has a greed factor g[i], which is the minimum size of a cookie that the child will be content with; and each cookie j has a size s[j]. If s[j] >= g[i], we can assign the cookie j to the child i, and the child i will be content. Your goal is to maximize the number of your content children and output the maximum number.

 

Example 1:

Input: g = [1,2,3], s = [1,1]
Output: 1
Explanation: You have 3 children and 2 cookies. The greed factors of 3 children are 1, 2, 3. 
And even though you have 2 cookies, since their size is both 1, you could only make the child whose greed factor is 1 content.
You need to output 1.

Example 2:

Input: g = [1,2], s = [1,2,3]
Output: 2
Explanation: You have 2 children and 3 cookies. The greed factors of 2 children are 1, 2. 
You have 3 cookies and their sizes are big enough to gratify all of the children, 
You need to output 2.

 

Constraints:

  • 1 <= g.length <= 3 * 104
  • 0 <= s.length <= 3 * 104
  • 1 <= g[i], s[j] <= 231 - 1

Companies: Adobe, Expedia, Amazon, Apple, Microsoft

Related Topics:
Array, Two Pointers, Greedy, Sorting

Solution 1.

// OJ: https://leetcode.com/problems/assign-cookies
// Author: github.com/lzl124631x
// Time: O(MlogM + NlogN)
// Space: O(1)
class Solution {
public:
    int findContentChildren(vector<int>& g, vector<int>& s) {
        sort(begin(g), end(g));
        sort(begin(s), end(s));
        int i = 0, j = 0, M = g.size(), N = s.size();
        for (; i < M && j < N; ++j) {
            if (g[i] <= s[j]) ++i;
        }
        return i;
    }
};