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Allow comparison when tips aren't identical #60

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ms609 opened this issue Nov 3, 2021 · 0 comments
Open

Allow comparison when tips aren't identical #60

ms609 opened this issue Nov 3, 2021 · 0 comments
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@ms609
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ms609 commented Nov 3, 2021

Simply modify QuartetStatus() to add u / r1 / r2 entries according to the number of quartets across all leaves not resolved by each tree, calculable by computing a confusion table across all leaves and using choose() before dropping non-overlapping leaves and launching tqDist.
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