能否根据结果文件汇总指标得到overall结果的脚本？

[Cppowboy]

已经按照readme流程跑完评测，得到评测结果文件。
英文
{"instruct_json": {"json_format_metric": 0.7756, "json_args_em_metric": 0.5518, "string_format_metric": 0.6203, "string_args_em_metric": 0.2131}, "review_str": {"parse_rate": 0.995, "review_quality": 0.63}, "plan_json": {"precision": 0.7321349206349207, "recall": 0.6362265284423179, "f1_score": 0.6686338217865152, "parse_rate": 0.792}, "plan_str": {"precision": 0.3754475468975469, "recall": 0.37650954080319404, "f1_score": 0.3518714429259886, "parse_rate": 0.636}, "reason_str": {"thought": 0.6100228428840637, "parse_rate": 1.0}, "retrieve_str": {"name": 0.068, "parse_rate": 1.0}, "understand_str": {"args": 0.598, "parse_rate": 1.0}, "rru_json": {"thought": 0.5686033221744001, "name": 0.116, "args": 0.5579963826997605, "parse_rate": 0.832}}

中文
{"instruct_json": {"string_format_metric": 0.7695, "string_args_em_metric": 0.3434, "json_format_metric": 0.9602, "json_args_em_metric": 0.6842}, "review_str": {"parse_rate": 0.995, "review_quality": 0.63}, "plan_json": {"precision": 0.7395571428571429, "recall": 0.6425877876509455, "f1_score": 0.6754312351792228, "parse_rate": 0.792}, "plan_str": {"precision": 0.4330866522366522, "recall": 0.4404432494062525, "f1_score": 0.4102201462600157, "parse_rate": 0.636}, "reason_str": {"thought": 0.6583724021911621, "parse_rate": 1.0}, "retrieve_str": {"name": 0.10020449897750511, "parse_rate": 1.0}, "understand_str": {"args": 0.4968684759916493, "parse_rate": 1.0}, "rru_json": {"thought": 0.6073757852361003, "name": 0.13701431492842536, "args": 0.4609381505678442, "parse_rate": 0.8609406952965235}}

论文附录中的计算方式有些麻烦，能否提供一个官方的保证正确的汇总指标方法？