1e5cbf22-97f5-4cbd-98f9-d04a91f25b0b.html

<h4>Cool Down Activity</h4>
<div class="os-raise-ib-cta" data-button-text="Solution" data-fire-event="Reveal1" data-schema-version="1.0">
  <div class="os-raise-ib-cta-content">
    <p>The solutions to this equation are \(x = \frac{3}{4}\) and \(x=\frac{1}{4}\). Show how to find those solutions by <span class="os-raise-ib-tooltip" data-schema-version="1.0" data-store="glossary-tooltip">completing the square</span>. \(x^2&minus;x+\frac{3}{16}=0\)</p>
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  <div class="os-raise-ib-cta-prompt">
    <p>Write down your answer, then select the <strong>solution</strong> button to compare your work.</p>
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<div class="os-raise-ib-content" data-schema-version="1.0" data-wait-for-event="Reveal1">
  <p>Compare your answer:</p>
  <p>\(\begin{array}{rcl}x^2-x+\frac3{16}&amp;=&amp;0\\x^2-x+\frac14&amp;=&amp;-\frac3{16}+\frac14=-\frac3{16}+\frac4{16}=\frac1{16}\\x^2-x+\frac14&amp;=&amp;\frac1{16}\\\sqrt{\left(x-\frac12\right)^2}&amp;=&amp;\sqrt{\frac1{16}}\\x-\frac12&amp;=&amp;\pm\frac14\\x-\frac12&amp;=&amp;\frac14\\x-\frac12&amp;=&amp;-\frac14\end{array}\)<br> \( \;\;\;\;\;\;\;\;\;\;x=\frac{1}{4} \text { and } x=\frac{3}{4}\) </p>
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